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MATH3503 Online Assignment 9

Arclength

Compute the arclengths of the following curves in the given intervals.
  1. \(\displaystyle y = \frac{2}{3}(x^2+1)^{3/2}\) in interval `1\le x\le 4`.
    Arclength =
    * Hint: \( 4a^2 + 4a + 1 = (2a+1)^2\)

  2. \(\displaystyle y = \frac{1}{4x^2}+\frac{x^4}{8}\) in interval `4\le x\le 5`.
    Arclength =
    * Hint: Express inside the square root as a single fraction, then use \( a^2 + 2a + 1 = (a+1)^2\)

  3. \(\displaystyle y = \frac{e^{3x}+e^{-3x}}{6}\) in interval `-7\le x\le 7`.
    Arclength =

  4. \(\displaystyle y = \ln(\sec x)\) in interval `-\pi/7\le x\le \pi/7`.
    Arclength =
    * Hint: \(\int \sec x\, dx = \ln(\tan x + \sec x) +\) constant.

    Surface Area

    Compute the surface area of each of the following solids of revolution in the given interval.
  5. \(\displaystyle y = 8x\) rotated about the `y`-axis in interval `0\le y\le 4`.
    Surface area =

  6. \(\displaystyle y = \sqrt{7x}\) rotated about the `x`-axis in interval `0\le x\le 5`.
    Surface area =

  7. \(\displaystyle x^{2/3}+y^{2/3} = 25\) rotated about the `x`-axis in interval `0\le x\le 125`.
    Surface area =

  8. An open pit has a paraboloid shape. Its height is 44 metres and the diameter of the opening is 165 metres. Compute the surface area of this pit.

    The paraboloid can be created by rotating

    `y=``x^2`   (Keep a few more significant digits.)
    about the `y`-axis. Thus,
    Surface area = m2



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